b^2=16/49

Solution for b^2=16/49 equation:

b^2=16/49

We move all terms to the left:

b^2-(16/49)=0

We add all the numbers together, and all the variables

b^2-(+16/49)=0

We get rid of parentheses

b^2-16/49=0

We multiply all the terms by the denominator


b^2*49-16=0

Wy multiply elements

49b^2-16=0

a = 49; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·49·(-16)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*49}=\frac{-56}{98}
=-4/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*49}=\frac{56}{98}
=4/7
$